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• 02-18-2018, 01:48 AM
Thanks that's enough Cheers!
7 replies | 428 view(s)
• 02-11-2018, 11:42 PM
the derivative is too complex to solve. I used the product rule . . .Area=(a-x) (square root 4ax) . . .dA/dx= u*dv/dx +v*du/dx where u=...
7 replies | 428 view(s)
• 02-10-2018, 07:47 PM
Is my term b really x=(y^2)/4a?
7 replies | 428 view(s)
• 02-10-2018, 07:36 PM
i. No dealing with negative values that complicate calculations ii.y=square root 4ax iii. Bringing in another variable it would be a-b where x=b is...
7 replies | 428 view(s)
• 02-08-2018, 11:39 PM
Having difficulty with the formulation of the equation from which the derivative is to be gained again. Here is the question: "(a) Draw a diagram...
7 replies | 428 view(s)
• 02-07-2018, 06:11 PM
It's the d^2 equation So I'm Ok now Thanks for your help
3 replies | 240 view(s)
• 02-07-2018, 05:54 PM
I found k cancels out during the calculation but I don't know which equation to plug w into to get d. It equals 16* root 3
3 replies | 240 view(s)
• 02-06-2018, 11:55 PM
Here is the question: "Engineers have determined that the strength s of a rectangular beam varies as the product of the width w and the square of...
3 replies | 240 view(s)
• 01-28-2018, 07:32 PM
Thanks for your input Still getting the hang of this process
12 replies | 450 view(s)
• 01-28-2018, 12:32 PM
I've never heard of a "perpendicular distance formula". Are you talking about the Distance Formula, which is used to find the distance between two...
12 replies | 450 view(s)
• 01-28-2018, 04:38 AM
Are you referring to the use of the perpendicular distance formula for the length of the line between the two parabolas?
12 replies | 450 view(s)
• 01-28-2018, 04:06 AM
thanks for your reply The figures for the minimum and maximum are given in the original drawing. Thought I gave them to you. Is there any point to...
12 replies | 450 view(s)
• 01-28-2018, 03:53 AM
thanks for your reply The figures for the minimum and maximum are given in the original drawing. Thought I gave them to you. Is there any point to...
12 replies | 450 view(s)
• 01-28-2018, 03:46 AM
12 replies | 450 view(s)
• 01-28-2018, 01:50 AM
Here is the question: the diagram(which I am unable to draw) has two parabolas in the first quadrant, one with a minimum at (3,7) and one with a...
12 replies | 450 view(s)
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