Register
Help
Remember Me?
What's New?
Forum
New Posts
FAQ
Calendar
Community
Member List
Forum Actions
Mark Forums Read
Quick Links
Today's Posts
View Site Leaders
Math Lessons by Subject
Calculators/Solvers
Advanced Search
Member List
Tuharramah
If this is your first visit, be sure to check out the
FAQ
by clicking the link above. You may have to
register
before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below.
Tuharramah
New Member
Find latest posts
Find latest started threads
Mini Statistics
Join Date
06-18-2017
Last Activity
Yesterday
02:52 AM
Tab Content
Tuharramah's Activity
About Me
Tab Content
All
Tuharramah
Photos
New Activity (
)
Please reload this page to view the 200+ new activity items that have been created.
Older Activity
06-22-2017,
07:58 AM
Tuharramah
started a thread
Trig:How do deal with absolute value of trigonometric functions
in
Geometry and Trig
\left(x\, -\, \dfrac{\pi}{2}\right)^2\, \cdot\, \big|\cos(x)\, +\, \sin(x)\big|\, =\, \dfrac{\pi^2}{4}\, \big(\cos(x)\, +\, \sin(x)\big) I went on...
see more
1 replies | 75 view(s)
06-20-2017,
01:21 PM
Tuharramah
replied to a thread
Trig equation: cos(3π/2−2x)+sin(π−3x)=sin(3x)−cos(x)
in
Geometry and Trig
Let's suppose it is. Because no information about domain is given
see more
10 replies | 240 view(s)
06-20-2017,
05:26 AM
Tuharramah
replied to a thread
Trig equation: cos(3π/2−2x)+sin(π−3x)=sin(3x)−cos(x)
in
Geometry and Trig
So it will be: -2sin (x)×cos (x)+cos (x)=0 2sin (x)×cos (x)-cos (x)=0 Cos (x) × (2sin (x) -1)=0 X1=90 X2=30 ..
see more
10 replies | 240 view(s)
06-19-2017,
02:33 PM
Tuharramah
replied to a thread
Trig equation: cos(3π/2−2x)+sin(π−3x)=sin(3x)−cos(x)
in
Geometry and Trig
https://i.imgur.com/KloQiX9.jpg Here is my solution As I said I couldn't upload it here
see more
10 replies | 240 view(s)
06-19-2017,
02:00 PM
Tuharramah
replied to a thread
Trig equation: cos(3π/2−2x)+sin(π−3x)=sin(3x)−cos(x)
in
Geometry and Trig
I got x as 30 deg. Unfortunately i couldn't upload my solution So is it correct answer?
see more
10 replies | 240 view(s)
06-19-2017,
10:12 AM
Tuharramah
started a thread
Trig equation: cos(3π/2−2x)+sin(π−3x)=sin(3x)−cos(x)
in
Geometry and Trig
You can see question in photo below Please tell me identities and/or other stuff to solve this.
see more
10 replies | 240 view(s)
06-19-2017,
02:26 AM
Tuharramah
replied to a thread
Simultaneous equations (tough one): 8^x 64^y = 128, sqrt[12y - 7] = x
in
Intermediate/Advanced Algebra
No ,mister, no typos
see more
18 replies | 516 view(s)
06-18-2017,
07:18 PM
Tuharramah
replied to a thread
Simultaneous equations (tough one): 8^x 64^y = 128, sqrt[12y - 7] = x
in
Intermediate/Advanced Algebra
Sqrt (12y-7)=x 8^x * 64^y=128 So 2^3x + 2^6y = 2^7 3*sqrt (12y-7) +6y =7 3*(12y-7)=(7-6y)^2 36y-21=49-84y+36y^2
see more
18 replies | 516 view(s)
06-18-2017,
07:10 PM
Tuharramah
replied to a thread
Simultaneous equations (tough one): 8^x 64^y = 128, sqrt[12y - 7] = x
in
Intermediate/Advanced Algebra
I did solve it for y ,Sir.However this is supposed to be solve without a calculator and when I saw decimals as roots I thought I made a mistake...
see more
18 replies | 516 view(s)
06-18-2017,
06:50 PM
Tuharramah
replied to a thread
Simultaneous equations (tough one): 8^x 64^y = 128, sqrt[12y - 7] = x
in
Intermediate/Advanced Algebra
It is originally 64 sir Did you solve it as 64y?
see more
18 replies | 516 view(s)
06-18-2017,
11:44 AM
Tuharramah
started a thread
Simultaneous equations (tough one): 8^x 64^y = 128, sqrt[12y - 7] = x
in
Intermediate/Advanced Algebra
Hello everyone! I tried but i couldn't solve it.Even several calculator apps on my phone couldn't. (Photomath .mathlab) Please explain in an "ok"...
see more
18 replies | 516 view(s)
More Activity
No More Results
No Recent Activity
About Tuharramah
Basic Information
Statistics
Total Posts
Total Posts
13
Posts Per Day
2.32
General Information
Last Activity
Yesterday
02:52 AM
Join Date
06-18-2017
Referrals
0