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• 11-10-2017, 09:56 PM
I'm assuming you would solve for the derivative as normal. Then since its f prime to the negative 1 power you would just change it to 1 / f prime....
7 replies | 425 view(s)
• 11-08-2017, 09:25 PM
Oh, I wasn't trying to be creative or anything. I just came across a question on a test I took recently that was similar to what I posted although a...
6 replies | 318 view(s)
• 11-06-2017, 10:28 AM
Thank you for the explanation. I don't know why they never talk about complex and imaginary numbers in math classes. They don't seem horrible but...
6 replies | 318 view(s)
• 11-05-2017, 03:29 PM
Hello again! I have a question about how you would find the derivative at an imaginary point. Lets say I had a function Y = sqrt(2 - x^2) ...
6 replies | 318 view(s)
• 10-30-2017, 09:56 PM
I apologize. I probably should have just edited the original post but I literally was just crunching numbers for a while after I posted the...
4 replies | 328 view(s)
• 10-30-2017, 09:34 PM
Hmmm.. I decided to approach this from the backend.. First I started with the maximum value of X or Y and subtracted that from 2017.. Ie.. I...
4 replies | 328 view(s)
• 10-30-2017, 08:57 PM
I recently took a test for a math competition for fun and I wasn't quite sure how to solve this problem. The test is long over but I still...
4 replies | 328 view(s)
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