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• 12-05-2017, 03:47 PM
@tkhunny great, I've got it now, thanks for clearing that up. It feels good to get that annoying bit of confusion out of the way.
10 replies | 320 view(s)
• 12-03-2017, 11:19 PM
Actually, having re-read that link to Paul's Online Maths Notes, it is indeed that a convergent series has a sequence that tends to 0. I can see the...
10 replies | 320 view(s)
• 12-03-2017, 10:56 PM
My understanding is that the divergence test only tells you that if the limit of the sequence a_n is not zero, then the series diverges, and that it...
10 replies | 320 view(s)
• 12-03-2017, 09:02 PM
So the sequence would look like a_0+a_1(-4)+a_2(16)+a_3(-64)+... I still don't see how the limit of a_n, \lim_\limits{n\to\infty}a_n, is 0?...
10 replies | 320 view(s)
• 12-03-2017, 12:10 AM
@tkhunny so I guess that would be a_0+a_1(-4)+a_2(16)+a_3(-64)... I still don't see how the limit of the sequence a_n, \lim\limits_{n\to\infty}a_n...
10 replies | 320 view(s)
• 12-02-2017, 06:35 PM
So the power series \sum_{n=0}^{\infty}a_n (x-4)^n converges at 0 and diverges at 9. How do we know that the limit of the sequence a_n is zero?...
10 replies | 320 view(s)
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