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• 12-07-2017, 07:07 PM
Many thanks for yout help:-)
12 replies | 599 view(s)
• 12-05-2017, 11:45 AM
We haven't covered Poisson, Beta or Weibull in our syllabus yet; but I don't know whether the method you're using is the correct one as it is...
12 replies | 599 view(s)
• 12-05-2017, 08:56 AM
But the answer for p in the question is 3/46 or 0.065, whereas I got 9/523.
12 replies | 599 view(s)
• 12-05-2017, 07:07 AM
If the mean is 9/23, and n=23, then p = 9/23 / 23 = 9/529
12 replies | 599 view(s)
• 12-03-2017, 06:13 PM
I genuinely don't know what to do after this.
12 replies | 599 view(s)
• 12-03-2017, 09:53 AM
The mean of a binomial distribution is np, but I don't know how to calculate the p in this particular question.
12 replies | 599 view(s)
• 11-28-2017, 07:29 PM
I'm really getting baffled with this question that has taken me far too long to complete and would love some guidance. An accident caused the...
12 replies | 599 view(s)
• 11-16-2017, 01:07 PM
You're right. I am confusing "r" with "R". Shouldn't the answer be y(r) = K(-1/r + 1/R) ? <== Good catch! Typos have been repaired, above..
5 replies | 299 view(s)
• 11-16-2017, 12:45 PM
OK. -1/R + F = 0 You are left with R = 1/F. Yet, if we subsitute this back into the general solution, we get K*0, as the two F's cancel each...
5 replies | 299 view(s)
• 11-16-2017, 06:56 AM
This is the process I went through: integrate both sides: 1/r^2 * dr = 1/K*dy = -1/r + C = Y/K + D = -1/r = Y/K + (D-C) = -1/r = Y/K + F ...
5 replies | 299 view(s)
• 11-15-2017, 06:37 PM
I have this question that I am struggling to see if it is correct or not. A quantity y(r) satisfies the first-order fifferential equation...
5 replies | 299 view(s)
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