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• 11-29-2017, 08:55 PM
Thanks for your feedback. I wanted Z rather than N, as even though a & b are expressed as cx & cy, they can be negatives as the a & b are in Z. ...
8 replies | 296 view(s)
• 11-29-2017, 06:07 PM
I hope I have solved it. Please vet the below proof. ------------------------------- I want to prove that if there are possibly divisors...
8 replies | 296 view(s)
• 11-29-2017, 12:58 AM
I want to prove a circular reasoning, as far as my understanding goes. I want to prove (i) that there are common divisors smaller than any linear...
8 replies | 296 view(s)
• 11-28-2017, 08:17 PM
I view it as a fundamental case in which need apply proof-constructing skills. I know that it is an involved proof, and by involved I mean that will...
8 replies | 296 view(s)
• 11-28-2017, 08:55 AM
In linear combinations, the basic property is if there are two integer quantities, say a and d, then any integer multiplied to the two will again...
8 replies | 296 view(s)
• 11-27-2017, 11:17 PM
A linear combination, ax+by+...=z, where a,b,...,z∈Z and x,y,...∈Z. It is bound to yield an integer by the closure property of integers under the...
0 replies | 97 view(s)
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