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• Today, 09:50 AM
Got it, AE and DE are the same length, so therefore it is an isosceles triangle, I used this formula to prove it |a| = √ax2 +√ ay2
11 replies | 215 view(s)
• Yesterday, 11:15 PM
Hmm this one i proving to be difficult I say... Let's see DA= (3,3) and DE = (3,0) and since AE is -DA +DE I would get AE = (0,-3)... and I'm not...
11 replies | 215 view(s)
• Yesterday, 09:57 PM
Hi Dr. Peterson sir, this is from the same question but they say using a vector method, if x=(2,0) and y= (1,1) prove triangle AED is isosceles. I...
11 replies | 215 view(s)
• 02-15-2018, 11:18 AM
AH yes, it was one 1.5, although I just did that by dividing each term, 1.5 is the scalar.
11 replies | 215 view(s)
• 02-15-2018, 08:42 AM
I wasn't sure about how they were scalar multiples, but I did see how (assume everything here is a vector) AP+PE = AE thus proving it's collinear, in...
11 replies | 215 view(s)
• 02-14-2018, 03:33 PM
In the figure, not drawn to scale, ABCD is a parallelogram such that (vec) DC = 3x and (vec) DA = 3y The point P is on DB such that DP:PB = 1:2 ...
11 replies | 215 view(s)
• 02-11-2018, 11:06 PM
Hi let's say we have a circle of diameter 15cm, and another circle of diameter 30cm. Is the second circle 4 times as large, or twice as large. ...
3 replies | 128 view(s)
• 02-09-2018, 09:51 AM
Here is a better diagram, As you can see the triangle formed by the horizontal plane corresponds with the bearing 210. My reasoning was I need 360...
7 replies | 264 view(s)
• 02-09-2018, 01:05 AM
Wow, I surprised myself, thanks dennis your clue made me see it clearly, it's two right angled triangles, from there I calculated XS and XR using tan...
7 replies | 264 view(s)
• 02-08-2018, 11:29 PM
No I actually wrote angle RTS is 10 degrees, perhaps it is difficult to see, well I showed it in case it had some relevance, I know exactly how to...
7 replies | 264 view(s)
• 02-08-2018, 10:11 PM
Hi, I don't have much of an attempt here, but here goes nothing: I'm trying to find the angle x marked in red, just trying to figure out methods...
7 replies | 264 view(s)
• 02-08-2018, 10:21 AM
Yes, I have solved the problem, I should have seen those shapes from the start.
10 replies | 333 view(s)
• 02-07-2018, 09:56 PM
Hey
10 replies | 333 view(s)
• 02-07-2018, 08:49 PM
Any ideas anyone?
10 replies | 333 view(s)
• 02-07-2018, 11:04 AM
No that really is all the information given, there is part 2 stating ''Given that AD = 18cm and angle EAD = 30 degrees, calculate the length of...
10 replies | 333 view(s)
• 02-07-2018, 09:57 AM
Sorry I meant angle ABC as the first one, typo.
10 replies | 333 view(s)
• 02-07-2018, 08:53 AM
Hello, here is a pentagon ABCDE and angle ABC=angle BCD=CDE Calculate giving a reason for each answer the magnitudes of angles (i) ABC and (ii)...
10 replies | 333 view(s)
• 02-06-2018, 05:11 PM
Got it: 1253x =5-18 = (53)3x= 5-18 59x=5-18 (because both bases are the same) 9x=-18
3 replies | 135 view(s)
• 02-06-2018, 04:54 PM
Solve this equation for X 1253x =1/518 So far I have , (125)3x * 518 = 1 What kind of steps are required here?
3 replies | 135 view(s)
• 02-05-2018, 03:36 PM
Indeed it was
19 replies | 713 view(s)
• 02-05-2018, 12:20 PM
I got it, I have to add, because it's North, and I'd round 59.9997 to 60 degrees, then I will add it to 63 ang get 123, then subtract that from 180...
19 replies | 713 view(s)
• 02-05-2018, 08:43 AM
OK I did the formula for an arc of longitude instead, l=C*(a)/360 6702.9=40217.6*(a)/360 (a) = (6702.9*360)/40217.6 (a) = 59.9997 degrees ...
19 replies | 713 view(s)
• 02-04-2018, 11:49 PM
I did this, using the formula for length of an arc of latitude l=C*(a)/360 so:6702.9= 40217.6*cos63*a/360 (a)= (6702.9*360)/(40217.6*cos63)...
19 replies | 713 view(s)
• 02-04-2018, 10:45 PM
Hmm... I keep getting 59 degrees, perhaps I'm doing this wrong? I'm actually unsure of the method I must use...
19 replies | 713 view(s)
• 02-03-2018, 11:21 PM
Well right, one is positive and one is negative... so it tells me they're on the same circle perhaps?
19 replies | 713 view(s)
• 02-03-2018, 09:33 PM
They differ by 40 degrees, I would guess it tells me that they're on the greenwich meridian circle?
19 replies | 713 view(s)
• 02-03-2018, 07:47 AM
The chapter is geometry 3, it starts off with circle theorems, then goes to trigonometrical identities, then goes to angles of elevation and...
19 replies | 713 view(s)
• 02-02-2018, 04:39 PM
To be honest I see no examples of where neither latitude nor longitude is the same. I'm really stumped and this topic is so foreign to me... I see...
19 replies | 713 view(s)
• 02-02-2018, 04:12 PM
Can anyone help?
19 replies | 713 view(s)
• 02-02-2018, 10:11 AM
Hi I've done a question on latitude and longitude. It states : Take the radius of the earth to be 6400km and pi to be 3.142. (i)The distance...
19 replies | 713 view(s)
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