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• 02-01-2018, 09:55 PM
This is my last post about anything other than the solution to the math question. The screenshot in the original post is self explanatory, other...
13 replies | 436 view(s)
• 02-01-2018, 08:04 PM
I am more confused than when I started this thread. If someone could just show me step by step, the answers to my questions in the OP, I would...
13 replies | 436 view(s)
• 02-01-2018, 03:16 PM
For this, I got, 1/2at^2=dx + c. I'm pretty sure dx + c is incorrect. I've had no trouble getting 1/2at^2 from at, the trouble is getting x out of...
13 replies | 436 view(s)
• 02-01-2018, 03:14 PM
Here's what I got: Vo^2 + 2Voa(t-to) + 2a(t-t0) Note, it's been a while since I've taken algebra and I'm working off 3 hours of sleep right now, so...
13 replies | 436 view(s)
• 02-01-2018, 03:11 PM
FYI - This is not a homework assignment. Instead, I am trying to understand something I am reading while self-studying calculus. It's been a while...
13 replies | 436 view(s)
• 02-01-2018, 07:19 AM
In that case, where did the following come from? This is from the screenshot in my first (original) post and it is to the right of the first equal...
13 replies | 436 view(s)
• 02-01-2018, 01:23 AM
In the lines below, where does the 2Vo come from? The 2Vo I speak of is to the right of the first equal sign. . . . . .v(t)^2\, =\, v_0^2\, +\,...
13 replies | 436 view(s)
• 01-29-2018, 10:46 PM
Oh thanks. I actually changed my initial answer above (one post above your last post). I am still confused but feel that a lot of progress has been...
11 replies | 327 view(s)
• 01-29-2018, 06:04 PM
The integral of 1 is done by adding 1 to the power of zero which results in a power of 1, leaving 1 as itself. Also, in this process 1 is divided by...
11 replies | 327 view(s)
• 01-29-2018, 03:41 PM
Right, the dt doesn't result in a t! Please excuse me, I'm very new to calculus. In fact the t in vt, comes from integration, as do all of the...
11 replies | 327 view(s)
• 01-29-2018, 02:30 PM
The t from dt isn't involved in integrating (duh, sorry to overlook something so obvious). So, we have v(dt) + at(dt). Then the bold t's exponent...
11 replies | 327 view(s)
• 01-29-2018, 01:44 PM
Why isn't it 1/3at^3? We start with t^2, and 2+1=3, so that makes it 1/3at^3, right? I mean, I know I'm wrong but just not sure why.
11 replies | 327 view(s)
• 01-29-2018, 01:09 PM
I attached a screenshot. Would someone remind me of the calculus step or rule that allows one to go from the upper line to the lower line and get...
11 replies | 327 view(s)
• 01-28-2018, 10:34 PM
The context is a graph with acceleration on the y axis, and time on the x axis. The x axis is labeled, 0, to, t1, t2, t3, t4, t', t. Then there is...
4 replies | 190 view(s)
• 01-28-2018, 08:09 PM
Why put primes on some of these t's but not on all of them? Can you give an example of where t is unequal to t prime in this case? . . . ....
4 replies | 190 view(s)
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