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• 01-28-2018, 09:29 PM
Thanks for the help! It makes a lot more sense now!
10 replies | 391 view(s)
• 01-28-2018, 06:11 PM
6 trials?
10 replies | 391 view(s)
• 01-28-2018, 04:49 PM
N is equal to number of trials.
10 replies | 391 view(s)
• 01-28-2018, 04:34 PM
The problem it self did not mention to use normal approximation. If binomial distribution was to be used (correct me if i'm wrong), N= 4, P=0.209.
10 replies | 391 view(s)
• 01-28-2018, 03:54 PM
I was able to identify that the question required normal approximation to the binomial distribution based on the probability of success being the...
10 replies | 391 view(s)
• 01-28-2018, 03:02 AM
I'm unsure on how to start this problem. I tried to make a tree diagram but to no avail did it help out. Question: On average, Mike Weir scores...
10 replies | 391 view(s)
• 01-28-2018, 02:47 AM
I got 1/2 for P(B'), checked the answers at it was right! Thanks for the fast reply! We have an exam on monday and i've been stuck on this all day...
3 replies | 247 view(s)
• 01-27-2018, 04:29 AM
So I'm having massive difficulty understanding and solving this problem: Given that P(A n B)=0.4, P(A n C)=0.2, P(B|A)=0.6 and P(B) = 0.5, Find the...
3 replies | 247 view(s)
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