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• 02-16-2018, 11:50 AM
I was having trouble getting this picture to be the right size, but the left hand side y axis has values of 50,100,150 X axis is labeled 2,4,6,8,10...
1 replies | 82 view(s)
• 02-07-2018, 11:01 AM
I tried to post earlier but apparently did not press the correct button. I did finally notice that e-2x(K+P0(e2x -1))would equal 0+P0*1 -0. This...
10 replies | 421 view(s)
• 02-06-2018, 08:01 PM
Actually, I did notice in the denominator, we have K+P0(e2x-1) This would be K +P0*e2x-P0 when multiplied by e-2x we would get 0 +P0*1-P0*0 = P0...
10 replies | 421 view(s)
• 02-06-2018, 04:54 PM
Dr. Peterson: I corrected the parentheses as you suggested It appears that if you multiply e2x with e-2x (e to negative exp power) you would get...
10 replies | 421 view(s)
• 02-06-2018, 10:55 AM
I had a math problem that I need help with. I already have the answer but I can't arrive at the explanation. It is the following: ...
10 replies | 421 view(s)
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