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• 12-07-2018, 12:33 AM
.5=.2(17/20)+.8(.5)(12/22+x/80) solve for x the .5 is because you have to average the 2 parts of the second course
3 replies | 310 view(s)
• 12-04-2018, 10:38 PM
pka gives a nifty way to solve the problem, using the general eqn of a line, but it is easier for me to understand using the defn of slope. in any...
7 replies | 313 view(s)
• 12-04-2018, 07:35 PM
to find a perpendicular slope. https://www.mathwarehouse.com/algebra/linear_equation/parallel-perpendicular-lines.php
7 replies | 313 view(s)
• 12-04-2018, 07:23 PM
this where I saw a problem if they are already paying 18$@$31.44 The overtime premium should be paid @ $18(47.16)(.5) correct? no no, the premium... 2 replies | 261 view(s) • 12-04-2018, 06:37 PM you are close x4-5x2+4=0 (x2-4)(x2-1)=0 (x-1)(x+1)(x-2)(x+2)=0 because one of the terms has to equal 0 x=-2,2, and x=-1,1 alternatively,... 34 replies | 1515 view(s) • 12-04-2018, 06:07 PM sinx replied to a thread Where do I start in Arithmetic a,b,and c are the salaries; x=scale factor x=6772.5 x=6772.5/ then the bonuses are x(0.2)a, x(0.15)b, and x(0.1)c 18 replies | 775 view(s) • 12-02-2018, 10:23 PM sinx replied to a thread Where do I start in Arithmetic 1 part = 6772.5/115=58.89 (divide by 115 to change your scale to 115%) 58.89 x 20=1177.82 x 3=3533.46 (bold is individual payments) 58.89 x 15 =... 18 replies | 775 view(s) • 12-02-2018, 09:45 PM x4-5x2+4=0 what drudge was saying; substitute w=x2 w2-5w+4=0 (w-4)(w-1)=0 w=4, and 1 then, since w=x2 x=sqrt4, and sqrt1 34 replies | 1515 view(s) • 12-02-2018, 09:24 PM sinx replied to a thread Differential in Calculus mv2z0(t)=mv2z(t)+mgz v2z0(t)=v2z(t)+gz 2vz0dvz0(t)=2vzdvz(t)+0 ----integration step, before this step and after is algebra----... 5 replies | 315 view(s) • 11-28-2018, 08:37 PM sinx replied to a thread Real Life Math Problem in Arithmetic type 2 per person =$73563.50/= $743.06 then, type 1 per person =$743.06(1.2)=$891.67 check; total type 2=$743.06(27)=\$20062.62 total type...
5 replies | 306 view(s)
• 11-16-2018, 10:18 AM
domain 1/(x-1); x can't be 1 (you cannot divide by 0) domain for x is all numbers except for 1 sqrt (x-1); x has to be >or= 1 (you cannot take...
17 replies | 822 view(s)
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