Write the equation
[math]2 \log_{ 3 }{ x } + x \log_{ 3 }{ (b + c) } - y ^ { 2 } = 3[/math]in a form not involving logarithm.
[math]2 \log_{ 3 }{ x } + x \log_{ 3 }{ (b + c) } - y ^ { 2 } = 3[/math]in a form not involving logarithm.
Solution
[math]2 \log_{ 3 }{ x } + x \log_{ 3 }{ (b + c) } - y ^ { 2 } = 3 \\
\implies[/math][math]\log_{ 3 }{ x ^ { 2 }} + \log_{ 3 }{ (b + c )} ^ { x } - y ^ { 2 } = 3[/math]Am stucked. What do I do next?