Simple Bernoulli trial: prob of pipe failure during inspection

I'm really getting baffled with this question that has taken me far too long to complete and would love some guidance.

An accident caused the catastrophic failure of metal pipes in a factory. There were

six metal pipes in the garage at any given time.

Table 1 shows the numbers of metal pipe failures that had occurred on

each of the 23 previous inspections.

**Table 1 Number of metal pipe failures**

Number of failed metal pipes 0 1 2 3 4 5 6

Number of inspections------16 5 2 0 0 0 0

(i) Let p be the probability that a pipe fails on an inspection. What

distribution is appropriate to describe the failure or non-failure of a

particular metal pipe on a particular inspection?

*For this I have said that this is a Bernoulli Distribution due to only two possible outcomes of failure and non-failure. *

(ii) A reasonable estimate of p is 3/46 or 0.065. Explain where this number comes from.

*This is where I am getting stuck on. I cannot work out what p is using the information they have provided. *

Many thanks for your help.