Hi. I am trying to solve the following problem without success.

Find the area of the surface generated by revolving the function y=[2x^(3/2)]/3 - [x^(1/2)]/2 between (0,0) and (9, 33/2), when the curve revolves around the y-axis.

I am stuck into not being able to change the equation from f(x) to f(y). My work ends at 36y^2=x(4x-3)^2.

(Calculus, Howard Anton, 3rd Edition, pg 417, exercise 25).

Thank you so much.