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Type: Posts; User: muzik

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  1. Thank you!! And thanks for the challenge. When...

    Thank you!!
    And thanks for the challenge. When I do get some time I'll give it a shot. Now that I know the answer. I need all the practice I can get. I got a test on Thursday but got to finish up...
  2. Ahhh so much better to determine the derivative...

    Ahhh so much better to determine the derivative first.

    The volume changes at a rate of 4/3*pi*48. Thanks all for you help.
  3. You're right. thanks

    You're right. thanks
  4. I am going to try and determine the derivative...

    I am going to try and determine the derivative first. then input the r value after. I didn't realize i could of factored out the constant. I'll see if that helps me on my next approach. I'm working...
  5. Well if continue as started. My lim is this big...

    Well if continue as started. My lim is this big long expression. And I'm lost on how to simplify it.
    So I will try to differentiate first as you suggested.

    Thanks
  6. Tangents and the Derivative of V=(4/3)* π * r^3 at a point (r = 4)

    What is the rate of change of the volume of a ball
    V=(4/3)* π * r^3
    with respect to the radius when the radius is equals=4​?


    The volume changes at a rate of?

    (Type an exact​ answer, using...
  7. Thank you for your help. I now understand the...

    Thank you for your help. I now understand the problem and got the answer correct. i was going to input 1 but waited like you said proof read before submit. I wasn't sure on 1 as the answer so i...
  8. Thanks for you help. i know understand. took me...

    Thanks for you help. i know understand. took me awhile.
  9. so.. =cos((3pi/2)-cos(3pi/2)) correct? ...

    so..

    =cos((3pi/2)-cos(3pi/2)) correct?
    =cos((3pi/2)-0)
    =cos(3pi/2)
    =0

    I got 1 because my algebra needs a lot of help. Thanks for you help.
  10. cos(pi/2)=0 see my answer in previous post....

    cos(pi/2)=0

    see my answer in previous post. does my work look correct? answer is 1?
  11. cos(-pi/2) ?

    cos(-pi/2) ?
  12. So i'm down to cos((-pi/2)-cos(-pi/2))...

    So i'm down to

    cos((-pi/2)-cos(-pi/2)) correct?
    =cos((-pi/2)-0)
    =cos(0-0)
    =cos (0)
    =1
  13. I was trying to simplify. The 7 with the...

    I was trying to simplify. The 7 with the denominator 14. so with out the cosine I was trying to simplify 7(-13*pi/14) so I that's how I got -13*pi/2. oops and I wrote -13*pi/7 in my earlier post.
    ...
  14. Thanks for the replies and sorry for the typos...

    Thanks for the replies and sorry for the typos
    Stapel, Yes that's correct interpretation.

    ok if I enter into calculator I get 0.8414.

    It's my last attempt on the answer for the problem. Does...
  15. Continuity lim x->-13*pi/14 cos(7x - cox(7x))

    Help please
    I should be able to just apply x into the function but I'm having trouble solving

    lim x->-13*pi/14 cos(7x-cox(7x))

    I get to

    cos(-13*pi/2 - cos(-13*pi/2))

    what next?
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