Many thanks for yout help:-)
Type: Posts; User: bulldog160
Many thanks for yout help:-)
We haven't covered Poisson, Beta or Weibull in our syllabus yet; but I don't know whether the method you're using is the correct one as it is different from the approximation you suggested.
But the answer for p in the question is 3/46 or 0.065, whereas I got 9/523.
If the mean is 9/23, and n=23,
then p = 9/23 / 23 = 9/529
I genuinely don't know what to do after this.
The mean of a binomial distribution is np, but I don't know how to calculate the p in this particular question.
I'm really getting baffled with this question that has taken me far too long to complete and would love some guidance.
An accident caused the catastrophic failure of metal pipes in a factory....
You're right. I am confusing "r" with "R".
Shouldn't the answer be y(r) = K(-1/r + 1/R) ? <== Good catch! Typos have been repaired, above..
OK.
-1/R + F = 0
You are left with R = 1/F. Yet, if we subsitute this back into the general solution, we get K*0, as the two F's cancel each other out.
This is the process I went through:
integrate both sides: 1/r^2 * dr = 1/K*dy
= -1/r + C = Y/K + D
= -1/r = Y/K + (D-C)
= -1/r = Y/K + F where F = D-c
Y = K(-1/r - F)
I have this question that I am struggling to see if it is correct or not.
A quantity y(r) satisfies the first-order fifferential equation r^2*dy/dr = K where r > 0 and K is a constant.
The...