# Search:

Type: Posts; User: bulldog160

1. ## Thread: Simple Bernoulli trial: prob of pipe failure during inspection

by bulldog160
Replies
12
Views
584

### Many thanks for yout help:-)

Many thanks for yout help:-)
2. ## Thread: Simple Bernoulli trial: prob of pipe failure during inspection

by bulldog160
Replies
12
Views
584

### We haven't covered Poisson, Beta or Weibull in...

We haven't covered Poisson, Beta or Weibull in our syllabus yet; but I don't know whether the method you're using is the correct one as it is different from the approximation you suggested.
3. ## Thread: Simple Bernoulli trial: prob of pipe failure during inspection

by bulldog160
Replies
12
Views
584

### But the answer for p in the question is 3/46 or...

But the answer for p in the question is 3/46 or 0.065, whereas I got 9/523.
4. ## Thread: Simple Bernoulli trial: prob of pipe failure during inspection

by bulldog160
Replies
12
Views
584

### If the mean is 9/23, and n=23, then p = 9/23...

If the mean is 9/23, and n=23,

then p = 9/23 / 23 = 9/529
5. ## Thread: Simple Bernoulli trial: prob of pipe failure during inspection

by bulldog160
Replies
12
Views
584

### I genuinely don't know what to do after this.

I genuinely don't know what to do after this.
6. ## Thread: Simple Bernoulli trial: prob of pipe failure during inspection

by bulldog160
Replies
12
Views
584

### The mean of a binomial distribution is np, but I...

The mean of a binomial distribution is np, but I don't know how to calculate the p in this particular question.
7. ## Thread: Simple Bernoulli trial: prob of pipe failure during inspection

by bulldog160
Replies
12
Views
584

### Simple Bernoulli trial: prob of pipe failure during inspection

I'm really getting baffled with this question that has taken me far too long to complete and would love some guidance.

An accident caused the catastrophic failure of metal pipes in a factory....
8. ## Thread: Getting 0 for a particular solution: r^2*dy/dr = K, r>0, K constant

by bulldog160
Replies
5
Views
298

### You're right. I am confusing "r" with "R". ...

You're right. I am confusing "r" with "R".

Shouldn't the answer be y(r) = K(-1/r + 1/R) ? <== Good catch! Typos have been repaired, above..
9. ## Thread: Getting 0 for a particular solution: r^2*dy/dr = K, r>0, K constant

by bulldog160
Replies
5
Views
298

### OK. -1/R + F = 0 You are left with R =...

OK.

-1/R + F = 0

You are left with R = 1/F. Yet, if we subsitute this back into the general solution, we get K*0, as the two F's cancel each other out.
10. ## Thread: Getting 0 for a particular solution: r^2*dy/dr = K, r>0, K constant

by bulldog160
Replies
5
Views
298

### This is the process I went through: ...

This is the process I went through:

integrate both sides: 1/r^2 * dr = 1/K*dy

= -1/r + C = Y/K + D
= -1/r = Y/K + (D-C)
= -1/r = Y/K + F where F = D-c
Y = K(-1/r - F)
11. ## Thread: Getting 0 for a particular solution: r^2*dy/dr = K, r>0, K constant

by bulldog160
Replies
5
Views
298

### Getting 0 for a particular solution: r^2*dy/dr = K, r>0, K constant

I have this question that I am struggling to see if it is correct or not.

A quantity y(r) satisfies the first-order fifferential equation r^2*dy/dr = K where r > 0 and K is a constant.

The...
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