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Type: Posts; User: Math1059

1. ## Thread: Normal Approximation: Mike scores a birdie on about 20.9% of all the holes he plays.

by Math1059
Replies
10
Views
370

### Thanks for the help! It makes a lot more sense...

Thanks for the help! It makes a lot more sense now!

by Math1059
Replies
10
Views
370

6 trials?
3. ## Thread: Normal Approximation: Mike scores a birdie on about 20.9% of all the holes he plays.

by Math1059
Replies
10
Views
370

### N is equal to number of trials.

N is equal to number of trials.
4. ## Thread: Normal Approximation: Mike scores a birdie on about 20.9% of all the holes he plays.

by Math1059
Replies
10
Views
370

### The problem it self did not mention to use normal...

The problem it self did not mention to use normal approximation. If binomial distribution was to be used (correct me if i'm wrong), N= 4, P=0.209.
5. ## Thread: Normal Approximation: Mike scores a birdie on about 20.9% of all the holes he plays.

by Math1059
Replies
10
Views
370

### I was able to identify that the question required...

I was able to identify that the question required normal approximation to the binomial distribution based on the probability of success being the same for each birdie. I'm assuming the equation...
6. ## Thread: Normal Approximation: Mike scores a birdie on about 20.9% of all the holes he plays.

by Math1059
Replies
10
Views
370

### Normal Approximation: Mike scores a birdie on about 20.9% of all the holes he plays.

I'm unsure on how to start this problem. I tried to make a tree diagram but to no avail did it help out.

Question:
On average, Mike Weir scores a birdie on about 20.9% of all the holes he plays....
7. ## Thread: Conditional Probability with 3 Events: P(A n B)=0.4, P(A n C)=0.2, P(B|A)=0.6 and...

by Math1059
Replies
3
Views
221

### I got 1/2 for P(B'), checked the answers at it...

I got 1/2 for P(B'), checked the answers at it was right! Thanks for the fast reply! We have an exam on monday and i've been stuck on this all day and understand it better now!
8. ## Thread: Conditional Probability with 3 Events: P(A n B)=0.4, P(A n C)=0.2, P(B|A)=0.6 and...

by Math1059
Replies
3
Views
221

### Conditional Probability with 3 Events: P(A n B)=0.4, P(A n C)=0.2, P(B|A)=0.6 and...

So I'm having massive difficulty understanding and solving this problem:
Given that P(A n B)=0.4, P(A n C)=0.2, P(B|A)=0.6 and P(B) = 0.5, Find the following:
a) P(A|B)
b) P(B')
c) P(A)
d)...
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