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Type: Posts; User: lookagain

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1. ## Thread: x^4/(3)√x Not sure what I did wrong (i got to x^(8/2)/3x^(1/2) )

by lookagain
Replies
5
Views
290

### If you intend for the problem to be equivalent to...

If you intend for the problem to be equivalent to \ \ \dfrac{x^{\frac{8}{2}}}{3x^{\frac{1}{2}}}, \ \ then you must put grouping symbols around the denominator,
such as in x^(8/2)/[3x^(1/2)].
...

by lookagain
Replies
10
Views
283

Nope. You are talking about your question which doesn't apply. You are off track and ignoring my points.

by lookagain
Replies
10
Views
283

### Why would I ask that, when it's not an...

Why would I ask that, when it's not an appropriate analogy?

I might write "x = 13 OR 14" for the solutions to a quadratic equation, where the plus sign of \pm corresponds
to the solution of...

by lookagain
Replies
10
Views
283

### I don't know what correspondence issue you're...

I don't know what correspondence issue you're referring to. "Plus or minus" is the same as "minus or plus," given that there is the
connector word "OR."

Example:

Show \pm\dfrac{f}{g} \ \ ...

by lookagain
Replies
10
Views
283

The plus-minus sign is a mathematical symbol with multiple meanings across mathematics and non-mathematics areas. And, it is used in different ways within mathematics itself,
sometimes, depending...
6. ## Thread: solve for (x+4)2 =x(x-4) +5

by lookagain
Replies
8
Views
1,060

### x-8 = \pm\sqrt{67}

x-8 = \pm\sqrt{67}
7. ## Thread: Using base units for Kinetic energy, verify by algebraic subs. correct units for vel.

by lookagain
Replies
5
Views
476

### No, you supposedly solved for one variable in an...

No, you supposedly solved for one variable in an equation and substituted in back into the same equation.
That would have given you an identity. You would have needed at least one other...
8. ## Thread: Inverse of the function: Find the range of: f(x) = 2x / sqrt(x^2 - 9)

by lookagain
Replies
6
Views
580

### y = \dfrac{2x}{\sqrt{x^2 - 9}} Regarding...

y = \dfrac{2x}{\sqrt{x^2 - 9}}

Regarding the range of the original function, y cannot belong to the interval [-2, 2].
9. ## Thread: Multiplicity Question: Is answer "7" for (x-3)^4( x-4)(x-5)(x-8)^2 ?

by lookagain
Replies
16
Views
1,518

### No, it does not necessarily refer to a plurality....

No, it does not necessarily refer to a plurality. It refers to the number of multiples of it, whether that be 0, 1, or a
whole number more than 1. A good definition is given in the beginning of...
10. ## Thread: How do I prove these two triangles are similar ?

by lookagain
Replies
3
Views
342

### You have a right angle in each of those two...

You have a right angle in each of those two triangles.

What do you conclude about the remaining two corresponding angles?
11. ## Thread: Multiplicity Question: Is answer "7" for (x-3)^4( x-4)(x-5)(x-8)^2 ?

by lookagain
Replies
16
Views
1,518

### (x - 3)^4(x - 4)(x - 5)(x - 8)^2 \ \ is a...

(x - 3)^4(x - 4)(x - 5)(x - 8)^2 \ \ is a polynomial that has four distinct zeros.

The zero 3 has multiplicity 4, because it occurs four times.

The zero 4 has multiplicity 1, because it...
12. ## Thread: Function f such that f (x) = ln (5×-10), for x >2; find range of function & inverse

by lookagain
Replies
2
Views
553

### You must have meant when x = 2.001, because...

You must have meant when x = 2.001, because ln(5*2.001 - 10) < 0.

cired2002, the numerical values for the domain of the original function are those
for the range of its inverse function. And...
13. ## Thread: I think I found the highest known prime number.

by lookagain
Replies
7
Views
1,023

### No, the proof does not conclude that. The...

No, the proof does not conclude that.

The proof concludes that either u is prime, or u has prime factors larger than the supposed largest prime in the list.
14. ## Thread: Stuck on how to do: given f(x)= 2x^2-5x+1 simplify f(x+5)-f(x)/5

by lookagain
Replies
7
Views
798

### 5x^(-3/6) + x^(-11/6) 5x^(-1/2) + x^(-11/6) ...

5x^(-3/6) + x^(-11/6)

5x^(-1/2) + x^(-11/6) . . . . I recommend you leaving it in this form. However, check with the instructions/instructor
to see if negative exponents are allowed in the...
15. ## Thread: Stuck on how to do: given f(x)= 2x^2-5x+1 simplify f(x+5)-f(x)/5

by lookagain
Replies
7
Views
798

### Type grouping symbols around your fractional...

Type grouping symbols around your fractional exponents. Use other grouping symbols for clarity is a recommendation. Space out your characters for more readability.
(I don't need the asterisk...
16. ## Thread: Integration problem: area enclosed by y=x3-3x2+3x and y=13x

by lookagain
Replies
9
Views
760

### No, show it as the following for your...

No, show it as the following for your instructor/course work and work it through. You should show your work here if you get stuck.

The area portion from x = -2 to x = 0:

...
17. ## Thread: Right triangle in a circle

by lookagain
Replies
7
Views
585

### Not necessarlly. What the OP gave to you is...

Not necessarlly. What the OP gave to you is flawed.

A right triangle is inscribed in a circle. The problem needs that.

It's 29/(2pi). You need grouping symbols.

by lookagain
Replies
3
Views
433

### Here, the domain of n is necessarily being taken...

Here, the domain of n is necessarily being taken as that of the integers, because the context is mathematical induction.

by lookagain
Replies
2
Views
345

### f(x) = -10x2+1 has no inverse function, because...

f(x) = -10x2+1 has no inverse function, because it is not a one-to-one function.

f(x) = -10x2+1, \ x \ge 0 is a one-to-one function, and it has an inverse function.

Likewise, f(x) = -10x2+1, ...
20. ## Thread: Limit Question- lim[x->2] (sqrt(6-x)-2)/(sqrt(3-x)-1)

by lookagain
Replies
2
Views
352

### If you wanted to use conjugates of the numerator...

If you wanted to use conjugates of the numerator and the denominator, you could begin with these steps:

\displaystyle\lim_{x\to \ 2} \ \dfrac{\sqrt{6 - x} \ - \ 2}{\sqrt{3 - x} \ - \ 1} \ = ...

by lookagain
Replies
7
Views
952

### Do not be name-calling on here. You must not be...

Do not be name-calling on here. You must not be clear that I was responding to a post that existed where yours is now.
I was civil toward you. I immediately stated the truth about it, and then...

by lookagain
Replies
7
Views
952

### No, it was done there, and it should not have...

No, it was done there, and it should not have been done. And clearly I stated that already. "Was" is past tense as concerns that person's post.
You're making up false arguments. You're making...

by lookagain
Replies
7
Views
952

No, you don't understand. That will never be done that way, because it needlessly and instantly throws the problem into more complexity
instead of going with the straightforward simplification. ...
24. ## Thread: Inverse functions of one-to-one functions

by lookagain
Replies
4
Views
494

### No, ksdhart2, that is not how the first one is to...

No, ksdhart2, that is not how the first one is to be done. It's on the same level of complexity as the work for f^{-1}(f(x)) that you showed below it.

f(f^{-1}(x)) = (\left( \sqrt[3]{x} + 3...

by lookagain
Replies
5
Views
691

### You are missing required grouping symbols. ...

You are missing required grouping symbols. Before you work on stapel's strategy, this is what you really intended:

1/(x + 1) - 2/(x + 1)^2 - (x^2 - 1)/(x+1)^3

That is, \ \ \dfrac{1}{x +...
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