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I did my best to solve this problem, but I have no idea how to do it. A lower case L is the absolute value sign in the problem. Given f(x)=6-2x-x^2, g(x)= l2x+1l, and h(x)=(x+3)/(x-5) and then the problem is: g(x+h) What I really don't understand for this is how do I figure out h? I don't...