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Many assumptions can be made as playing it's best wasn't established whether its to kill when it can or not. Likewise, a win wasn't specified, but based on chess rules I would think a win is only if one player has killed the three other players.. Assuming kill when you can, I drew out some...

you have a 3 by 3 chessboard with 3 white pawns and 3 black pawns. given white goes first and both teams play their best what is the outcome? is the outcome a draw always since pawns can only move forward and kill diagonally. This means that the middle pawn can only kill either the left or...

Giving the question, we know that 3 less than twice x is, (2x - 3) We also know that 2 more than the quantity of 3 times x is, (3x + 2) Taking the product of them we get (2x - 3) (3x + 2) Using FOIL(first outside inside last) we get: 6x^2 + 4x - 9x - 6 By simplifying we get 6x^2 - 5x - 6...

I'm not sure whether or not this is correct, but I am going to go with no. A counter-example could be. Let x = y = z = 1 Let c = 5 which would give us cx - cy + 1 = e^cz 5 - 5 + 1 = e^(5)(1) 1 = e^5 which is not true.

Let H be a subset of R3, defined by: W={(x, y, z) : x - y + 1 = e^z}. Is H a subspace of R3? To determine if H is a subspace of R3, we need to satisfy the three properties. The zero vector of R3 is in H because substituting x = y = z = 0 into x - y + 1 = e^0 gives us a valid expression. I am...

Sorry, I misread the "do not round your answer part."

They look good to me.

If each man sits beside his wife the men and women would have designated seating so to speak. If men and women only alternate, this means they don't have to sit beside their wive and they can sit beside any females. You can try treating the men and women as one person if they have to alternate.

I saw this a while ago, I got a kick out of it. I also like the one where it has a triangle and says find x with x being the hypotenuse. The person circles x and writes beside it "found it."

Rearrange it so you have the t isolated. 42 = 7t - 42 42 + 42 = 7t 84 = 7t 84 / 7 = t 12 = t

C\; = \;\Pi \; \times \;d Is the equation to find the circumference of a circle. You know the radius is 6. The diameter is twice the radius. This makes the diameter 12. C\; = \;\Pi \; \times \;12 \cr C\; = \;37.7 \cr

I meant for an answer. What is the velocity and 6 seconds?

What does your homework say? Also what is the velocity and 6 seconds?

Posting your work so we can see what you have done would be better next time. However, **Edit** Vector symbols don't seem to show up for me, so I left them out - Make sure you include them. \[ \begin{array}{l} a\; = \;\frac{v}{t} \\ a\; = \;\frac{{ - 16\;m/s\; - \;0\;m/s}}{{7\;s\; -...

Thanks for the help!

I am so confused with this. Would r sqrt 2 not be the diameter? AO^2 + OB^2 = AB^2 AO = r and OB = r thus, r^2 + r^2 = AB^2 2r^2 = AB^2 sqrt both sides r sqrt2 = AB then the radius would be 1/2 r sqrt 2 A = pi (1/2 r sqrt2)^2 / 2 A = pi 1/4 r^2 (2) / 2 A = 2pi r^2 / 8 A = pi r^2 / 4 is that...

I understand that the first one is suppose to be the area of a semicircle. the area of a circle is pir^2 since it is a semi circle we would need to divide that by 2. therefore it would be pir^2 / 2. To find out the diameter you would use pythagorean. By doing this you would have the diameter...

I don't understand the first one.

Can you please explain it? I don't understand how you got r^2 pi / 4 for the area of the semicircle.

The right angle triangle has legs of length r and a right angle at O. A quarter of a circle is consturcted with the centre O and a radius of r. A semicircle is construted with a diameter of AB. Prove that the area of the shaded lune is equal to the area of triangle AOB. Area of the...