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    If a, b, c > 0 and a + b + c = 3, prove that abc =< 1

    I have used the inequality Cosi but do not make results
  2. L

    If a, b, c > 0 and a + b + c = 3, prove that abc =< 1

    help me Prove that if a, b, c is the length of three sides of a triangle have equal perimeter, then 3: 3a + 3b ^ 2 ^ 2 ^ 2 + 3c + 4abc ≥ 13
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