Home
Forums
New posts
Search forums
What's new
New posts
Latest activity
Log in
Register
What's new
Search
Search
Search titles only
By:
Latest activity
Register
Menu
Log in
Register
Install the app
Install
Forums
Search
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Search results
L
If a, b, c > 0 and a + b + c = 3, prove that abc =< 1
I think the wrong problem
leviethoang1012
Post #4
Dec 4, 2013
Forum:
Beginning Algebra
L
If a, b, c > 0 and a + b + c = 3, prove that abc =< 1
I have used the inequality Cosi but do not make results
leviethoang1012
Post #3
Dec 4, 2013
Forum:
Beginning Algebra
L
If a, b, c > 0 and a + b + c = 3, prove that abc =< 1
help me Prove that if a, b, c is the length of three sides of a triangle have equal perimeter, then 3: 3a + 3b ^ 2 ^ 2 ^ 2 + 3c + 4abc ≥ 13
leviethoang1012
Thread
Dec 4, 2013
Replies: 4
Forum:
Beginning Algebra
Forums
Search
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.
Accept
Learn more…
Top