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    With square matrix B=P^(-1) A P, prove det(tI-B)=det(tI-A)

    Opps sorry, i saw the instruction after i post My only step can do is prove that det(A) =det(B) But I found that det(tI-A) ≠det(tI-B) if i only know det(A) =det(B) So i think i went to a wrong direction I was thinking in diagonalization, but no idea Thank you!
  2. 1

    With square matrix B=P^(-1) A P, prove det(tI-B)=det(tI-A)

    With square matrix B=P-1AP, prove det(tI-B)=det(tI-A) thanks!!! I have one more question: If a matrix P can be expressed as V-1CV must C be diagonal? thanks!
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