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  1. J

    Ampitude of a wave: f(t)= cos(t)+sin(t+(pi/4))

    thanks for that. I get. √((1/√2)2 + (1 + 1/√2)2) =1.8478 regards JT
  2. J

    Ampitude of a wave: f(t)= cos(t)+sin(t+(pi/4))

    Evening all I have a function f(t)= cos(t)+sin(t+(pi/4)) To find the amp of this wave do i just use the general constant formula (not sure its called that) asinx+bcosv= Sqrt(a^2+b^2)sin(x+v) so the amp is sqrt(1^2+1^2) so sqrt2 or 1.4142? thanks JT
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