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Help much appreciated I did mistakenly say that 3^1 should be 1. I've tried it multiple times on paper and I couldn't find the mistake I made. High school was 11 years ago guys and I have to work the problems to understand the rules. Now I got my shame message out of the way. I think you guys...

ahhhhhhh.... the original question was to simplify and leave with out radicals. I used multiplying powers to find that (3)[3^(x/2)]^2 = (3)(3^x) ...for 2/1 * x/2 simplifies to x....leaves me with (3)(3^x). I'm assuming I'm making some simple stupid mistake here...I've gotten through the rest of...

ok... I got that far and when I get to the last computation in that line of simplification 3 * 3^x and I get 9^x... excuse my ignorance, where does the ^x+1 come from, specifically the + 1 part? I'm assuming that the terms are not like and you cannot multiply 3^x * 3???? what am i missing...

Hey guys, so this is my first post so bare with me. I am working a problem set in a precalc workbook and came across this: (3)(3x/2)2 The answer i always arrive at no matter how I work it comes out 9^x but the answer sheet on the problem set says that it is 3^(x+1). Can someone give me a...