Search results

  1. M

    Completing Integral problem using substitution: Integral [ ( ln sqr(x) ) / x ] dx

    Now i see what you were trying to show me. Sorry a little hard to understand with all the brackets. Thank you for you help.
  2. M

    Completing Integral problem using substitution: Integral [ ( ln sqr(x) ) / x ] dx

    Thank you all for you help! I got the help I was looking for.
  3. M

    Completing Integral problem using substitution: Integral [ ( ln sqr(x) ) / x ] dx

    I see, now I understand. Thank you very much.
  4. M

    Completing Integral problem using substitution: Integral [ ( ln sqr(x) ) / x ] dx

    I see the square root x, in the equation. I just don't understand where the 1/4 went or how it contributes to the square root x. Or I'm not understanding your comment correctly.
  5. M

    Completing Integral problem using substitution: Integral [ ( ln sqr(x) ) / x ] dx

    The subtitution used in the example u = ln(x) after using the log rule. So using the log rule Integral ( ln sqrt(x) / x ) dx = Integral ( ln (x)^1/2 / x ) dx , use log rule to move 1/2 in front of ln so, = Integral ( 1/2 ln(x) / x ) dx , now use u = ln(x). and so forth.. but back to...
  6. M

    Completing Integral problem using substitution: Integral [ ( ln sqr(x) ) / x ] dx

    I've used "View an example" on the Pearson website for a Integral problem using substitution. I understand the process the example had until I got to the end. The problem is an indefinite integral Integral [ ( ln sqr(x) ) / x ] dx The answer came out to ( ln sqr(x) )^2 + C The part I...
  7. M

    Tangents and the Derivative of V=(4/3)* π * r^3 at a point (r = 4)

    Thank you!! And thanks for the challenge. When I do get some time I'll give it a shot. Now that I know the answer. I need all the practice I can get. I got a test on Thursday but got to finish up on homework first.
  8. M

    Tangents and the Derivative of V=(4/3)* π * r^3 at a point (r = 4)

    Ahhh so much better to determine the derivative first. The volume changes at a rate of 4/3*pi*48. Thanks all for you help.
  9. M

    Tangents and the Derivative of V=(4/3)* π * r^3 at a point (r = 4)

    I am going to try and determine the derivative first. then input the r value after. I didn't realize i could of factored out the constant. I'll see if that helps me on my next approach. I'm working it out now. Thank you for the suggestion
  10. M

    Tangents and the Derivative of V=(4/3)* π * r^3 at a point (r = 4)

    Well if continue as started. My lim is this big long expression. And I'm lost on how to simplify it. So I will try to differentiate first as you suggested. Thanks
  11. M

    Tangents and the Derivative of V=(4/3)* π * r^3 at a point (r = 4)

    What is the rate of change of the volume of a ball V=(4/3)* π * r^3 with respect to the radius when the radius is equals=4​? The volume changes at a rate of? (Type an exact​ answer, using pi as​ needed.) So i started with r = 4, insert into the equation. V=(4/3)*pi*r^3 V= (4/3)*pi*(4)^3...
  12. M

    Continuity lim x->-13*pi/14 cos(7x - cox(7x))

    Thank you for your help. I now understand the problem and got the answer correct. i was going to input 1 but waited like you said proof read before submit. I wasn't sure on 1 as the answer so i waited till i was sure.
  13. M

    Continuity lim x->-13*pi/14 cos(7x - cox(7x))

    Thanks for you help. i know understand. took me awhile.
  14. M

    Continuity lim x->-13*pi/14 cos(7x - cox(7x))

    so.. =cos((3pi/2)-cos(3pi/2)) correct? =cos((3pi/2)-0) =cos(3pi/2) =0 I got 1 because my algebra needs a lot of help. Thanks for you help.
  15. M

    Continuity lim x->-13*pi/14 cos(7x - cox(7x))

    cos(pi/2)=0 see my answer in previous post. does my work look correct? answer is 1?
  16. M

    Continuity lim x->-13*pi/14 cos(7x - cox(7x))

    cos(-pi/2) ?
  17. M

    Continuity lim x->-13*pi/14 cos(7x - cox(7x))

    So i'm down to cos((-pi/2)-cos(-pi/2)) correct? =cos((-pi/2)-0) =cos(0-0) =cos (0) =1
  18. M

    Continuity lim x->-13*pi/14 cos(7x - cox(7x))

    I was trying to simplify. The 7 with the denominator 14. so with out the cosine I was trying to simplify 7(-13*pi/14) so I that's how I got -13*pi/2. oops and I wrote -13*pi/7 in my earlier post. I'm just thinking the answer is not in decimal form. Thanks for your help.
  19. M

    Continuity lim x->-13*pi/14 cos(7x - cox(7x))

    Thanks for the replies and sorry for the typos Stapel, Yes that's correct interpretation. ok if I enter into calculator I get 0.8414. It's my last attempt on the answer for the problem. Does 0.8414 sound right? The requirement is to "Simplify your answer" Usually it will say up to 4...
Top