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It takes both the top and bottom to make a can.

doesn't (-7)2​=49?

I disagree. Learning math and geometry/trig is a series of small steps of learning. Each step concludes with an 'aha' moment, when what seemed to be complex becomes simple.

a) the question is what is the length of side ac sin65=ab/ac; you know ab=25 feet, solve for ac b) the question is what is the length of side ad sin62=ad/ab; you know ab=25 feet, solve for ad redraw the picture for yourself with sides labeled, and apply sin=opposite/hypotenuse. [rule 1-...

1+2/3=5/3

because the sin of an angle is never larger than 1 (or -1). [@ 900 and 2700​]

general eqn for hyperbola with origin (0,0) is; x2/a2-y2/b2=1 where a=x intercept and b=co-vertices so the specific eqn for this hyperbola is; x2-y2/8=1 because it intersects x at -1,1, and has covertices=+-sqrt8

have you tried trig identity, double angle? sub u=2x? can you show what you have tried?

.5=.2(17/20)+.8(.5)(12/22+x/80) solve for x the .5 is because you have to average the 2 parts of the second course

pka gives a nifty way to solve the problem, using the general eqn of a line, but it is easier for me to understand using the defn of slope. in any case, you must first recognize that perpendicular slopes are negative reciprocals. e.g. the line y=-2/3x-8/9 has a slope of -2/3 the negative...

to find a perpendicular slope. https://www.mathwarehouse.com/algebra/linear_equation/parallel-perpendicular-lines.php

this where I saw a problem if they are already paying 18$ @ $31.44 The overtime premium should be paid @ $18(47.16)(.5) correct? no no, the premium is 18($31.44)(.5)=$282.96; not $379.82, the premium is how much is added to your regular pay for those hours. you get the same answer either way 18...

you are close x4-5x2+4=0 (x2-4)(x2-1)=0 (x-1)(x+1)(x-2)(x+2)=0 because one of the terms has to equal 0 x=-2,2, and x=-1,1 alternatively, you dont have to factor (x2-4)(x2-1)=0 (x2-4)(x2-1)=0 again, because one of the terms has to equal 0 x=sqrt4, and x=sqrt1 x=-2,2, and x=-1,1

a,b,and c are the salaries; x=scale factor x[3a(0.2)+3b(0.15)+(0.10)c]=6772.5 x=6772.5/[(0.6)a+(0.45)b+(0.1)c] then the bonuses are x(0.2)a, x(0.15)b, and x(0.1)c

1 part = 6772.5/115=58.89 (divide by 115 to change your scale to 115%) 58.89 x 20=1177.82 x 3=3533.46 (bold is individual payments) 58.89 x 15 = 883.35 x 3= 2650.05 58.89 x 10= 588.9 total, of underlined amts =6772.41, (= .09 left over)

x4-5x2+4=0 what drudge was saying; substitute w=x2 w2-5w+4=0 (w-4)(w-1)=0 w=4, and 1 then, since w=x2 x=sqrt4, and sqrt1

mv2z0(t)=mv2z(t)+mgz v2z0(t)=v2z(t)+gz 2vz0dvz0(t)=2vzdvz(t)+0 ----integration step, before this step and after is algebra---- 2vz0dvz0(t)=2vzdvz(t) vz0dvz0=vzdvz

type 2 per person =$73563.50/[27+60(1.2)]= $743.06 then, type 1 per person =$743.06(1.2)=$891.67 check; total type 2= $743.06(27)=$20062.62 total type 1=$891.67(60)=$53500.20 grand total = $73562.82 =$0.68 left over.

domain 1/(x-1); x can't be 1 (you cannot divide by 0) domain for x is all numbers except for 1 sqrt (x-1); x has to be >or= 1 (you cannot take sqrt of a negative number) domain for x is all numbers >or= 1

can you write the expression you wish to integrate?