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    Integrand Using Series: e^(4t) / (e^(2t) + 3*e^(t) + 2)

    The problem is the Integrand of e^(4t)/(e^(2t)+3*e^(t)+2) Any ideas on how to begin would be greatly appreciated.
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    Integration Problem: find the Integral of Sqrt(x^2+2x)dx

    Re: Integration Problem Thanks. That last part was the one I overlooked.
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    Integration Problem: find the Integral of Sqrt(x^2+2x)dx

    Re: Integration Problem Thanks for your help.
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    Integration Problem: find the Integral of Sqrt(x^2+2x)dx

    Re: Integration Problem Thanks for the help so far. By reduction formula, do you mean the one from the Table of Integrals. If so, I'm not allowed to use that. Any other way?
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    Integration Problem: find the Integral of Sqrt(x^2+2x)dx

    I need to find the Integral of Sqrt(x^2+2x)dx. It is a Integration by Partial Fractions exercise. I don't even know where to start. Any help on where to start would be greatly appreciated. If this helps, the solution given by the book is: (1/2)[(x+1)Sqrt(x^2+2x)-ln|x+1+Sqrt(x^2+2x)|]+c
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    Newton's Method to find 100^(1/100) correct to 8 dec. places

    Re: Newton's Method I'm using f(x)=x^100-100 Am I incorrect?
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    Newton's Method to find 100^(1/100) correct to 8 dec. places

    I need help on a Newton's Method problem. I have to "Use Newton's method to approximate the given number correct to eight decimal places". The number is the hundredth root of 100 (100^(1/100)). When done on calculator, the result is 1.04712855. I've tried the approximation but am not able to...
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    Calculus Limit: limit, x-->a, of [cos(x) - cos(a)] / (x - a)

    Re: Calculus Limits Sorry for not posting any details of my progress (I hadn't achieved anything as I was stuck and didn't see the relation to the definition of derivative). But thanks to both of you I see it now. Thanks
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    Calculus Limit: limit, x-->a, of [cos(x) - cos(a)] / (x - a)

    I have a Calculus project. I have to find the following limit without using L'Hospital: Limit as x approaches a (x->a) of (cos(x)-cos(a))/(x-a) The result is -sin(a) Thanks in advance.
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