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Re: need help with this problem please post edited. thanks :)

Re: need help with this problem please Just use the order of operations to do out the problem. -2(15/-5)-6/2+9 you start with executing any parenthesis -2(-3)-6/2+9 You then do exponents. but their are none. -2(-3)-6/2+9 You then do multiplication and division. starting from left to...

ah thats why i see it as root2 over 2. its the rationalized form.

I never knew that you could think of the sin and cos of a 45 degree angle as 1 over root2. I got root 2 over 2 drilled into me when i hit trig :D Now i will store that little piece of info away and im sure it will help me in the future. It must be like html headers, except it is for math...

I wanted to ask one more question that isnt math oriented. :) You guys show your work with images. How do you do this? I want to know so that when I help others my work looks better. Thanks again to all those who helped me with the proof. I 100% understand it now!! Knight

Big glenn, that is very helpful. I understand everything except for how you go from step 2 to step 3. Im going to take some time to analyze it and see if I can figure out what you did on my own. That was VERY helpful and once i totally understand step 2 to step 3 I will be where I want to be...

I'm not 100% sure what you mean. but... If you are saying "opposite numbers" as in say, 2 and -2 then the reciprocal of each number would still be opposite 2, -2 are opposite numbers 2 -----------------> 1/2 ----reciprocal---- -2 -----------------> -1/2 (1/2) and (-1/2) are opposite...

I think I'm drawing closer to fully understanding this proof. I 100% understand the result you got. It is a double angle identity, so that means it is easily provable at that point But I'm still a little dumbfounded on how you got their. Ok so we start with: 1.) sin(2x) = 2sin^2(x + ?/4) -1...

I know the values for cos pi/4 and sin pi/4 (root2 over 2) Now by expanding the squared bracket you mean just squaring everything inside? so Apply the ^2 to all the terms on the right side 2sin(x)cos(x) = 2(sin^2(x)cos^2(?/4) + cos^2(x)sin^2(?/4))-1 cos and sin of pi/4 = root2 over 2...

I was not sure if I should post this in the trig section or in this section. I figured I would post it here in the calculus section because it is a problem I have run into in my pre calc class. I'm having major trouble on a proof where I have to prove sin(2x) = 2sin^2(x+(?/4))-1 So far I...