crybloodwing
New member
- Joined
- Aug 22, 2017
- Messages
- 29
Sketch the area between two curves and then find the area. This is using summations.
y=2x1/3, y=(1/8)x2, 0<=x<=6
So I got the sketch okay, but I feel I am making some mistake somewhere in the algebraish part.
IGNORE THIS WORK! CHECK THE COMMENTS. I posted a new version with the right integration and still got the wrong answer. Look at that!
1. Subtract the bottom curve from the other. [2x1/3-(1/8)x2]
2. Get the antiderivtive. [(3/4)(2x4/3)-(1/24x3)]=[6/4x4/3-(1/24)x3]
3. Plug the values 6 and 0 in and solve
[(6/4)(64/3)-(1/24)(63)]-[(6/4)(04/3)-(1/24)(03)]
=[(6/4)(64/3)-9]-0
The book says the answer is (47/3)-[(9/2)(121/3) which is between 5 and 6. However, when I plug the value above into a calculator, I get between 7 and 8. Where am I going wrong?
y=2x1/3, y=(1/8)x2, 0<=x<=6
So I got the sketch okay, but I feel I am making some mistake somewhere in the algebraish part.
IGNORE THIS WORK! CHECK THE COMMENTS. I posted a new version with the right integration and still got the wrong answer. Look at that!
1. Subtract the bottom curve from the other. [2x1/3-(1/8)x2]
2. Get the antiderivtive. [(3/4)(2x4/3)-(1/24x3)]=[6/4x4/3-(1/24)x3]
3. Plug the values 6 and 0 in and solve
[(6/4)(64/3)-(1/24)(63)]-[(6/4)(04/3)-(1/24)(03)]
=[(6/4)(64/3)-9]-0
The book says the answer is (47/3)-[(9/2)(121/3) which is between 5 and 6. However, when I plug the value above into a calculator, I get between 7 and 8. Where am I going wrong?
Last edited: