veronicadeno
New member
- Joined
- Jan 23, 2011
- Messages
- 13
Find dy/dx:
y=[sin(x+5)]^(5/4)
So far I have this:
y=[sin(x+5)]^(5/4)
y'={[(5/4)cosx(x+5)]^(1/2)} [cos(x+5)] (1)
There are only answers to odd numbered questions in the back of my textbook & this is an even numbered problem. I'm not sure where to go from here or if I've used chain rule the right way.
y=[sin(x+5)]^(5/4)
So far I have this:
y=[sin(x+5)]^(5/4)
y'={[(5/4)cosx(x+5)]^(1/2)} [cos(x+5)] (1)
There are only answers to odd numbered questions in the back of my textbook & this is an even numbered problem. I'm not sure where to go from here or if I've used chain rule the right way.