Justinetea
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- Jan 8, 2018
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I have to find y, but i don't have a formula to solve that one, any idea?
L−1[e(-2πs-2s)/(s2-4)]
L−1[e(-2πs-2s)/(s2-4)]
Inverse laplace transform, formula help please: L−1[e(-2πs-2s)/(s2-4)]
- Thread starter Justinetea
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Can you do \(\displaystyle \dfrac{1}{s^{2}-4}\)?
Can you do \(\displaystyle \dfrac{e^{-s}}{s^{2}-4}\)?
Can you do \(\displaystyle \dfrac{e^{-(s+2)}}{s^{2}-4}\)?
Can you do \(\displaystyle \dfrac{e^{-(s+\pi)}}{s^{2}-4}\)?
Show your work. Let's see where it leads.
Can you do \(\displaystyle \dfrac{e^{-s}}{s^{2}-4}\)?
Can you do \(\displaystyle \dfrac{e^{-(s+2)}}{s^{2}-4}\)?
Can you do \(\displaystyle \dfrac{e^{-(s+\pi)}}{s^{2}-4}\)?
Show your work. Let's see where it leads.
Justinetea
New member
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- Jan 8, 2018
- Messages
- 2
unsolved
for the firs question it is sin2t
second , should i treat e^-s as a constant?
i saw too a formula where F(s)=e-cs/s and than f(t)=uc(t)=u(t-c) but it still doesn't solve my problem
for the firs question it is sin2t
second , should i treat e^-s as a constant?
i saw too a formula where F(s)=e-cs/s and than f(t)=uc(t)=u(t-c) but it still doesn't solve my problem
D