doughishere
Junior Member
- Joined
- Dec 18, 2015
- Messages
- 59
yo. whats the missing math here.......i cant seem to figure it out tonight.
\(\displaystyle f(f^{-1}(x)) = \frac{1}{3(\frac{1-2x}{3x})+2}=...=x\)
right? the composition of a function and its inverse is x?
i just get \(\displaystyle \frac{1-2x}{x}+2 = \frac{1}{x}\)
Edit: nevermind i got it....writing it down on here seemed to help for some reason.
\(\displaystyle f(f^{-1}(x)) = \frac{1}{3(\frac{1-2x}{3x})+2}=...=x\)
right? the composition of a function and its inverse is x?
i just get \(\displaystyle \frac{1-2x}{x}+2 = \frac{1}{x}\)
Edit: nevermind i got it....writing it down on here seemed to help for some reason.
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