2021econ2012
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- Sep 6, 2017
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My calc class is studying basic derivatives, and I'm stuck on a problem.
The problem is f(r) = (4/3) * pi * r3 The answer is 4pir2
\(\displaystyle \dfrac{d}{dr}\, \left[\dfrac{4\pi r^3}{3}\right]\)
. . .\(\displaystyle =\, \dfrac{4\pi}{3}\, \cdot\, \dfrac{d}{dr}\left[r^3\right]\)
. . .\(\displaystyle =\, \dfrac{4\pi\, \cdot\, 3r^2}{3}\)
. . .\(\displaystyle =\, 4\pi r^2\)
I understand that the power rule calls for the exponent of 3 to be brought to the front and then the exponent is decreased by one. I also understand that the 3 in the denominator cancels out with the 3 in the numerator.
What I don't understand is why the constant rule (that the derivative of a constant is equal to 0) doesn't apply to the 4 and pi in this case.
Could someone please help explain this? Many thanks.
The problem is f(r) = (4/3) * pi * r3 The answer is 4pir2
\(\displaystyle \dfrac{d}{dr}\, \left[\dfrac{4\pi r^3}{3}\right]\)
. . .\(\displaystyle =\, \dfrac{4\pi}{3}\, \cdot\, \dfrac{d}{dr}\left[r^3\right]\)
. . .\(\displaystyle =\, \dfrac{4\pi\, \cdot\, 3r^2}{3}\)
. . .\(\displaystyle =\, 4\pi r^2\)
I understand that the power rule calls for the exponent of 3 to be brought to the front and then the exponent is decreased by one. I also understand that the 3 in the denominator cancels out with the 3 in the numerator.
What I don't understand is why the constant rule (that the derivative of a constant is equal to 0) doesn't apply to the 4 and pi in this case.
Could someone please help explain this? Many thanks.
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