Finding the x-intercept of f(x) = x + cos(x)

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swjafar

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f(x) = x + cos(x)
I found the y-intercept to be 1
f(0) = 0 + cos(0) = 1

However, when trying to solve for f(x) = 0, I get -x = cos(x).

From this point it seems to be a trial and error game or calls for the use of some complex function to solve for x. Is there a simpler way?
 
swjafar said:
f(x) = x + cos(x)
I found the y-intercept to be 1
f(0) = 0 + cos(0) = 1

However, when trying to solve for f(x) = 0, I get -x = cos(x).

From this point it seems to be a trial and error game or calls for the use of some complex function to solve for x. Is there a simpler way?
Click to expand...
No, I think you have it. There are many interesting methods for finding numerical solutions where your algebraic efforts prove insufficient. Some require the Calculus. (derivatives can be helpful.) Some don't.
 
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