y = 1 + a1/(x-a1) + a2/((x-a1)(x-a2)) + a3/((x-a1)(x-a2)(x-a3)) then dy/dx ...

y = 1 + a1/(x-a1) + a2/((x-a1)(x-a2)) + a3/((x-a1)(x-a2)(x-a3))

then dy/dx = (y/x) (a₁/(a₁ - x) + a₂/(a₂ - x) + a₂/(a₂ - x))

You'll have to show us how you got there. Where did a3 go?

abrakadabra said:

y = 1 + a1/(x-a1) + a2/((x-a1)(x-a2)) + a3/((x-a1)(x-a2)(x-a3))

then dy/dx = (y/x) (a₁/(a₁ - x) + a₂/(a₂ - x) + a₂/(a₂ - x))

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