Saraghtera
New member
- Joined
- Feb 1, 2018
- Messages
- 5
Hello
I'm posting this after an extra math lesson where teacher tries to help us who need it. She couldn't break it to me though so I'm asking if there's a person who can use words that I understand and make me learn this one equation.
We calculated this:
y' - 2y = sin x to the point where we got:
-sin x(B + 2A) + cos x(A-2B) = sin x
I just can get my head around the next part even with the help of my teacher. I wish there was a way to make me understand how to solve that and why is the solution like it is. I don't want a straight answer but to understand.
I would start by moving all the sin f(x):s to the right and cos to the left but teacher said it would "break the idea". She then started to explain something about multipliers the sin functions have, which are -1 and 1. After that I have no idea how her thought progressed.
I'm in distress for not understanding something that seems so obvious to the other people!
Joona
I'm posting this after an extra math lesson where teacher tries to help us who need it. She couldn't break it to me though so I'm asking if there's a person who can use words that I understand and make me learn this one equation.
We calculated this:
y' - 2y = sin x to the point where we got:
-sin x(B + 2A) + cos x(A-2B) = sin x
I just can get my head around the next part even with the help of my teacher. I wish there was a way to make me understand how to solve that and why is the solution like it is. I don't want a straight answer but to understand.
I would start by moving all the sin f(x):s to the right and cos to the left but teacher said it would "break the idea". She then started to explain something about multipliers the sin functions have, which are -1 and 1. After that I have no idea how her thought progressed.
I'm in distress for not understanding something that seems so obvious to the other people!
Joona