Solving -3 + (100)(29*10^{-12})(e^(V_D/(27*10^{-3})) = V_b
- Thread starter zorro
- Start date
D
Deleted member 4993
Guest
You have variables Vb and VD here. Whose value do you want to calculate? What is the value of the other one?
both are VD:
\(\displaystyle -3\, +\, (100)\,(29\, \times\, (10^{-12})\, \left(e^{^{V_D}\big/{29\, \times\, 10^{-3}}}\, -\, 1\right)\, =\, V_D\)
Last edited by a moderator:
D
Deleted member 4993
Guest
You have a nonlinear equation.
What methods have you been taught to solve these types of equations?
What are your thoughts?
Please share your work with us ...even if you know it is wrong.
If you are stuck at the beginning tell us and we'll start with the definitions.
You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL:
http://www.freemathhelp.com/forum/announcement.php?f=33
mmm4444bot
Super Moderator
- Joined
- Oct 6, 2005
- Messages
- 10,902
The given equation represents an equality between a transcendental function and an algebraic function. This type of equation cannot be solved in terms of elementary functions.
You can take a numerical approach (eg: Newton's Method), to approximate solution(s).
Exact solution(s) may be expressed, in terms of the LambertW function (generally not covered in undergraduate calculus courses).
You can take a numerical approach (eg: Newton's Method), to approximate solution(s).
Exact solution(s) may be expressed, in terms of the LambertW function (generally not covered in undergraduate calculus courses).