Calculate f(-1)

NoahSilva2

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Sep 20, 2017
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I need help solving this one problem assigned for homework in my Algebra II HOnors class.

Let f(x)=ax^2+bx+c such that
f(0)=f(1)
f(2)=2f(1)
f(3)=16
Calculate f(-1)

I'm lost, and have no idea where to start. All I've been able to work out is that -a=b because

f(0)=f(1)

f(0)=a(0)^2+b(0)+c
f(0)=c

f(1)=a(1)^2+b(1)+c
f(1)=a+b+c

a+b+c=c
a+b=0
-a=b
 
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What are your thoughts?

Please share your work with us ...even if you know it is wrong.

If you are stuck at the beginning tell us and we'll start with the definitions.

You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL:

http://www.freemathhelp.com/forum/announcement.php?f=33

I'm asking for help...I don't have any thoughts. Or work. I need help solving for f(-1). f(0)=f(1), f(2)=2f(1), and f(3)= 16 are GIVEN. Hope that helps?
 
No, that doesn't help.

You demonstrated in your edited post that you DO have an idea where to start.

Now, move on to the next hint and do the same thing. You're almost there.
 
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