Need help w/: Let point M be outside parallelogram ABCD s.t. angle MAB = angle MCB

ebwoolf96

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Let point M be outside the parallelogram ABCD such that angle MAB = angle MCB. Prove that angle AMC = angle CMB. (What I have been trying to do is prove that triangle MDE is congruent to triangle MBC however I am having trouble doing this !!) Note: AC is not parallel to EF.

MCProve that angle AMC = angle CMB. AMC=CMBan




 
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