markl77
New member
- Joined
- Feb 5, 2017
- Messages
- 33
Two Different Word Probs: Two consecutive numbers & how many students went on trip
The first word problem says :
Two consecutive numbers are represented by (x) and (x+1). If 6 is added to the first number and two is subtracted from the second number, the quotient of the new numbers is (9/2). Determine the numbers algebraically.
Here is my work
x, (x+1)
1/[(6+x)(x-2)] = (9/2)
2 = 9[(x+6)(x-2)]
=9x^2+36x-110
But when I factor this, I just get horrible numbers that cant be the numbers for the equation. The problem I have is setting it up, I have no idea how to do that and the textbook offers no help.
The second word problem says :
A club collected the same amount from each student going on a trip. When six students could not go, each of the remaining students were charged an extra 3$. If the total cost was $540, how many students went on the trip?
540 = 1/x + 1/(x+3)
540x+1620=x+3+x
538x=-1617
which gives me a negative number of course...
The first word problem says :
Two consecutive numbers are represented by (x) and (x+1). If 6 is added to the first number and two is subtracted from the second number, the quotient of the new numbers is (9/2). Determine the numbers algebraically.
Here is my work
x, (x+1)
1/[(6+x)(x-2)] = (9/2)
2 = 9[(x+6)(x-2)]
=9x^2+36x-110
But when I factor this, I just get horrible numbers that cant be the numbers for the equation. The problem I have is setting it up, I have no idea how to do that and the textbook offers no help.
The second word problem says :
A club collected the same amount from each student going on a trip. When six students could not go, each of the remaining students were charged an extra 3$. If the total cost was $540, how many students went on the trip?
540 = 1/x + 1/(x+3)
540x+1620=x+3+x
538x=-1617
which gives me a negative number of course...