Determine Factors: if we divide by 2 for x + 1x = 20, then...

[KWF]

To find the solution to the following, divide by 2: x + 1x = 20
20/2 = 10 solution 10 + 10 = 20

How would the answer for the following be determined by dividing the sum 15 by 2 equal 7 1/2?

x + 1/2x = 15

Is there another solution other than 15 divided by 1 1/2?

 

[Deleted member 4993]

To find the solution to the following, divide by 2: x + 1x = 20
20/2 = 10 solution 10 + 10 = 20

How would the answer for the following be determined by dividing the sum 15 by 2 equal 7 1/2?

x + 1/2x = 15

Is there another solution other than 15 divided by 1 1/2?

x + 1x = 20

2x = 20 ..... divide by 2: x + 1x = 20

(2x)/2 = 20/2

x = 10

 

[KWF]

x + 1x = 20

2x = 20 ..... divide by 2: x + 1x = 20

(2x)/2 = 20/2

x = 10

I want to thank you for the reply, but it only repeated the solution to my first example.

How would the answer for the following be determined by dividing the sum 15 by 2 equal 7 1/2?

x + 1/2x = 15

Is there another solution other than 15 divided by 1 1/2?

 

[mmm4444bot]

I think Subhotosh was showing that you can combine like-terms on the left-hand side of the equation before dividing.

x + 1/2*x = 15

3/2*x = 15

You may now solve for x, by multiplying each side of the equation by the reciprocal of 3/2 (same as dividing by 3/2).

This is a linear equation, so there is only one solution. :cool:

 

[Deleted member 4993]

I want to thank you for the reply, but it only repeated the solution to my first example.

How would the answer for the following be determined by dividing the sum 15 by 2 equal 7 1/2?

x + 1/2x = 15

Is there another solution other than 15 divided by 1 1/2?

In that case you would NOT divide by 2!

Instead you would divide by 1.5 (or 3/2).

x + 1/2x = 15

1.5 * x = 15

x = 10