# Thread: Area in Circle with two chords

1. Originally Posted by bfischer
Not sure how you got your [answer] …
Do you have any questions about what I wrote below?

Originally Posted by mmm4444bot
Subtracting the area of the isosceles triangle from the area of the sector yields the area of the segment (i.e., the upper-shaded region in your diagram). Add that to half the circle's area.

2. Originally Posted by bfischer
Hi:

Not sure how you got your answers... but this is where I'm at with this problem.

Thanks,

Brett
Flip the triangle around its base (within the circle) and look at the resulting figure....

3. ## Area

Hi:

Here's the picture revised.

Thanks!

Brett

4. Hmmmm....you know the central angle is 120 degrees;
and you know the radius: have you tried calculating
the segment instead? Here's the formula:

http://mathworld.wolfram.com/CircularSegment.html

5. ## Got it!

Hello:

Thank you!

Finally, I had the "Aah-Ha" moment.

For beginners... I think math authors think we know what certain angles are going to be of shapes (like the triangle) when they give us dimensions of objects "not to scale".

In all, I'm very appreciated of your help.

How easy was this!!!

Bye,

Brett

6. You got it Brett!

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