solving for a and b in a linear equation

fantasy22

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Joined
Aug 8, 2017
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1
hello
can someone please help me solve this problem
x-2y+3z=4
2x-3y+az=5
3x-4y+5z=b
what are the values of a and b
a) Has no solution;
b) Has a unique solution;
c) Has infinitely many solutions.

thank s :)
 
hello
can someone please help me solve this problem
x-2y+3z=4
2x-3y+az=5
3x-4y+5z=b
what are the values of a and b
a) Has no solution;
b) Has a unique solution;
c) Has infinitely many solutions.

thank s :)
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x-2y+3z=4
2x-3y+az=5
3x-4y+5z=b
What are the values of a and b [for which the above system of equations:]
a) Has no solution;
b) Has a unique solution;
c) Has infinitely many solutions.
First, solve the system to get answers in terms of "a" and "b". What do you get?

Once you've replied with that information, we can proceed to the next step. Thank you! ;)
 
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