simplify & fractorise: find the sum of 2a + 3b + 5c and a + b -c, ...

[add]

Hello after a having left maths alone for awhile im trying to brush up on my skills but im having problems with a few simplify and fracotrise questions i was hoping someone could lead me in the right direction?

so first question

find the sum of 2a + 3b + 5c and a + b -c so i have basically added a and b to together and taken 1 off c to make it 3a + 4b -4c

2nd question
simplify
2^4x3^-5
------------
3^2x2^-1

simplify
12s + 3st

and then the transpose x + 1 = 2y to make y the subject


what sort of formula am i looking for one these questions?

and thanks
---
r

 

[tkhunny]

Your a, b, c results looks good.

Use exponent rules to simplify the second one.

Distributive property. Opinions vary as to whether that is actually simplified.

Use your best algebra on the last and let's see what you get.

 

[add]

2^4x3^-5
------------
3^2x2^-1


so i have 2x4 x 3 x -5 = -120
-------
3x2 x 2- 4 = 8 8

atm these are muti choice so i know that the answer has to be
a, 2^5 x3^7
b, 2^3
-----
3^7
c 2^3 x3^-3

is there a way of using the answers to quickly find the correct one?

 

[stapel]

2^4x3^-5
------------
3^2x2^-1

To learn how to form math as text, please try here. I think your expression means the following:

. . . . .\(\displaystyle \dfrac{(2^4)(x)(3^{-5})}{(3^2)(x)(2^{-1})}\)

I have no idea why the variable is plopped down in the middle like this. Is the above correct? If not, please reply with clarification.

I'm afraid I don't understand the characters, strings, etc, that follow, so I can't comment. Sorry.