mistyblinx
New member
- Joined
- Sep 21, 2017
- Messages
- 1
Find the volume of a solid generated by revolving about the line y=-1 the region bounded by 2y=x+3 and the outside of the curves y^2+x=0 and y^2-4x=0.
I graphed it using Desmos to visualize what I needed to do. I think I'm looking for the 2 sections bounded by 2y=x+3 and y=-1, squeezed between the two parabolas. The range between (-1, 2) to be more specific. At this point I have tried to wrap my brain around what would be the be way to approach this question. Should I use the area formula for the 4 separate quadrants? For example in quadrant one take the integral of (2y=x+3)-(2y=x+3), (0,2) with respect to x and then do that for each section. They put the Area into the volume formula. Should I take the area from (-1,2) and then subtract the area of the parabolas? I think I'm just at a loss for where to start this problem. I would appreciate any help.
I graphed it using Desmos to visualize what I needed to do. I think I'm looking for the 2 sections bounded by 2y=x+3 and y=-1, squeezed between the two parabolas. The range between (-1, 2) to be more specific. At this point I have tried to wrap my brain around what would be the be way to approach this question. Should I use the area formula for the 4 separate quadrants? For example in quadrant one take the integral of (2y=x+3)-(2y=x+3), (0,2) with respect to x and then do that for each section. They put the Area into the volume formula. Should I take the area from (-1,2) and then subtract the area of the parabolas? I think I'm just at a loss for where to start this problem. I would appreciate any help.