What are the steps to get from f(x) = -10x2+1 to ±√(1-x) / √10 or
E evking New member Joined Aug 30, 2017 Messages 13 Sep 21, 2017 #1 What are the steps to get from f(x) = -10x2+1 to ±√(1-x) / √10 or Last edited by a moderator: Sep 21, 2017
K ksdhart2 Senior Member Joined Mar 25, 2016 Messages 1,297 Sep 21, 2017 #2 What are your thoughts? How far did you get using the standard stepshttp://www.coolmath.com/algebra/16-inverse-functions/05-how-to-find-the-inverse-of-a-function-01 to find a function's inverse? Please re-read the Read Before Postinghttps://www.freemathhelp.com/forum/threads/41536-Read-Before-Posting!! thread that's stickied at the top of each subforum, and comply with the rules therein. Namely, please share with us any and all work you've done on this problem, even the parts you know for sure are wrong.
What are your thoughts? How far did you get using the standard stepshttp://www.coolmath.com/algebra/16-inverse-functions/05-how-to-find-the-inverse-of-a-function-01 to find a function's inverse? Please re-read the Read Before Postinghttps://www.freemathhelp.com/forum/threads/41536-Read-Before-Posting!! thread that's stickied at the top of each subforum, and comply with the rules therein. Namely, please share with us any and all work you've done on this problem, even the parts you know for sure are wrong.
L lookagain Elite Member Joined Aug 22, 2010 Messages 3,187 Sep 21, 2017 #3 evking said: What are the steps to get from f(x) = -10x2+1 to ±√1-x / √10 or View attachment 8527 Click to expand... f(x) = -10x2+1 has no inverse function, because it is not a one-to-one function. f(x) = -10x2+1, \(\displaystyle \ x \ge 0\) is a one-to-one function, and it has an inverse function. Likewise, f(x) = -10x2+1, \(\displaystyle \ x \le 0\) is a one-to-one function, and it has an inverse function.
evking said: What are the steps to get from f(x) = -10x2+1 to ±√1-x / √10 or View attachment 8527 Click to expand... f(x) = -10x2+1 has no inverse function, because it is not a one-to-one function. f(x) = -10x2+1, \(\displaystyle \ x \ge 0\) is a one-to-one function, and it has an inverse function. Likewise, f(x) = -10x2+1, \(\displaystyle \ x \le 0\) is a one-to-one function, and it has an inverse function.
