Using base units for Kinetic energy, verify by algebraic subs. correct units for vel.

[JimCrown]

Using the base units for Kinetic energy verify by algebraic substitution the correct units for velocity.

How would I come to the answer? What method would I use? I have been on google trying to find methods. I was told the answer is : v = ms^-1

But I have no idea how to get there. Please help

 

[Deleted member 4993]

Using the base units for Kinetic energy verify by algebraic substitution the correct units for velocity.

How would I come to the answer? What method would I use? I have been on google trying to find methods. I was told the answer is : v = ms^-1

But I have no idea how to get there. Please help

How are kinetic energy and speed related?

 

[JimCrown]

typo

How are kinetic energy and speed related?

I do not know exactly. I know that the answer needs to be v = (the kinetic energy base units)

I do not know a method to work the question out

 

[JimCrown]

http://www.physicsclassroom.com/class/energy/Lesson-1/Kinetic-Energy

Rearrange first

KE = 0.5 * M * V^2

Multiply by 2

2KE = MV^2

Divide by V^2

M = 2KE/V^2

2KE = MV^2

Divide by M

V^2 = 2KE/M

Then square root of both sides

V = √2ke/√m

Then substitute that equation into KE = 0.5 * M * V^2

KE = 0.5 * M * √2ke/√m^2

Is that right?

 

[lookagain]

Rearrange first

KE = 0.5 * M * V^2

Multiply by 2

2KE = MV^2

Divide by V^2

M = 2KE/V^2

2KE = MV^2

Divide by M

V^2 = 2KE/M

Then square root of both sides

V = √2ke/√m

Then substitute that equation into KE = 0.5 * M * V^2

KE = 0.5 * M * √2ke/√m^2

Is that right?

No, you supposedly solved for one variable in an equation and substituted in back into the same equation.
That would have given you an identity. You would have needed at least one other nonequivalent equation
for substitution.