Originally Posted by

**byedabeast**
So I am in my last year of pharmacy school and upon graduation I will be working for the Federal Bureau of Prisons....as a prison pharmacist. Long story short, there are 98 federal prisons, 22 of which I wouldn't mind being placed at (for various reasons), but each year only about 10 prisons have vacancies. So therefore, I would have to hope that one of my 22 preferred prisons is in that list of 10 job openings.

That's the story, here's the simplified question: What is the probability that if 10 numbers are chosen between 1-98, that at least one of them is 22 or below?

I'm not in any type of math class, just looking for help. I calculated it to be upwards of 90% but I'm interested to see what other people come up with. Let me know if anyone needs further clarification.

Thanks!

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