Any help would be great.
Find;
i) res[exp(1/z)/z^2-16,4]
ii) res[exp(1/z)/z^2-16,-4]
iii) res[exp(1/z)/z^2-16,0]
And then describe all contours of the integral
iv) ~ exp(1/z)/z^2+16 dz = 0
Any help would be great.
Find;
i) res[exp(1/z)/z^2-16,4]
ii) res[exp(1/z)/z^2-16,-4]
iii) res[exp(1/z)/z^2-16,0]
And then describe all contours of the integral
iv) ~ exp(1/z)/z^2+16 dz = 0
Well, there is one thing that can help. If you're in Complex Analysis, you should know the difference between
1/z^2 - 16 = [tex]\dfrac{1}{z^{2}}-16[/tex]
and
1/(z^2 - 16) = [tex]\dfrac{1}{z^{2}-16}[/tex]
After that, have you considered identifying the Order of the Pole and simply computing the appropriate limit?
Please follow the forum guidelines - this includes showing YOUR work.
"Unique Answers Don't Care How You Find Them." - Many may have said it, but I hear it most from me.
Apologies, it was an error on my part, I forgot to include the brackets.
So far I have exp(1/z)/(z+4)(z-4) so z = +/- 4
For z = 4 ; exp(1/4)/(4+4)/(4-4) = 0.161
For z = -4 ; exp(1/-4)/(-4-4)/(-4+4) = -0.097
For z = 0; exp(1)/-1 = -2.72
For the second part, the contour exp(1/z)/(z+4i)(z-4i);
z = +/- 4i
2(pi)i * [exp(1/4i)/8i + exp(1/-4i)/-8i]
Not sure if I am correct so any bit of help would be great. Thanks
Let's get a little better with notation, please. Good notation will save you. It matters.
How can you write "/(4-4)" with a straight face? That's no good.
Are you sure about z = 0?
"Unique Answers Don't Care How You Find Them." - Many may have said it, but I hear it most from me.
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