Q. With a fair coin, my opponent flips 50 times, with fair odds, ie I double my bet on a win.

The average outcome is 25 wins, 25 losses.

However, if I make the assumption that I will win at least 15 times, how do I

proportion my bets

to be ahead at the 15th win, whilst minimising bets?

Further, write an

equation to illustrate this with e= expected wins, n= total flips.

I know e=15, n=50.

I think if c=expected wins at any point in the series, bet=1+(losses/c) should be right, but

it does not take into account n.

I have asked an engineering graduate who is stuck. Any help, please?

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